From: chrysn Date: Fri, 16 Mar 2012 01:36:36 +0000 (-0400) Subject: the algorithms required for map plugin sorting X-Git-Url: https://sipb.mit.edu/gitweb.cgi/ikiwiki.git/commitdiff_plain/128234cde1ed0504d6beb0b2d10544feb2d77809 the algorithms required for map plugin sorting --- diff --git a/doc/todo/sort_parameter_for_map_plugin_and_directive/python_algorithms.py b/doc/todo/sort_parameter_for_map_plugin_and_directive/python_algorithms.py new file mode 100644 index 000000000..ccee8185d --- /dev/null +++ b/doc/todo/sort_parameter_for_map_plugin_and_directive/python_algorithms.py @@ -0,0 +1,81 @@ +testdata = "c/3 a b d b/1 c/1 c/2/x c/2 c".split(" ") + +def strategy_byearlychild(sequence): + """Sort by earliest child + + When this strategy is used, a parent is displayed with all its children as + soon as the first child is supposed to be shown. + + >>> strategy_byearlychild(testdata) + ['c', 'c/3', 'c/1', 'c/2', 'c/2/x', 'a', 'b', 'b/1', 'd'] + """ + + # first step: pull parents to top + def firstchildindex(item): + childindices = [i for (i,text) in enumerate(sequence) if text.startswith(item + "/")] + # distinction required as min(foo, *[]) tries to iterate over foo + if childindices: + return min(sequence.index(item), *childindices) + else: + return sequence.index(item) + sequence = sorted(sequence, key=firstchildindex) + + # second step: pull other children to the start too + return strategy_byparents(sequence) + +def strategy_byparents(sequence): + """Sort by parents only + + With this strategy, children are sorted *under* their parents regardless of + their own position, and the parents' positions are determined only by + comparing the parents themselves. + + >>> strategy_byparents(testdata) + ['a', 'b', 'b/1', 'd', 'c', 'c/3', 'c/1', 'c/2', 'c/2/x'] + """ + + def partindices(item): + return tuple(sequence.index(item.rsplit('/', i)[0]) for i in range(item.count('/'), -1, -1)) + + return sorted(sequence, key=partindices) + +def strategy_forcedsequence(sequence): + """Forced Sequence Mode + + Using this strategy, all entries will be shown in the sequence; this can + cause parents to show up multiple times. + + The only reason why this is not the identical function is that parents that + are sorted between their children are bubbled up to the top of their + contiguous children to avoid being repeated in the output. + + >>> strategy_forcedsequence(testdata) + ['c/3', 'a', 'b', 'd', 'b/1', 'c', 'c/1', 'c/2', 'c/2/x'] + """ + + # this is a classical bubblesort. other algorithms wouldn't work because + # they'd compare non-adjacent entries and move the parents before remote + # children. python's timsort seems to work too... + + for i in range(len(sequence), 1, -1): + for j in range(1, i): + if sequence[j-1].startswith(sequence[j] + '/'): + sequence[j-1:j+1] = [sequence[j], sequence[j-1]] + + return sequence + +def strategy_forcedsequence_timsort(sequence): + sequence.sort(lambda x,y: -1 if y.startswith(x) else 1) + return sequence + +if __name__ == "__main__": + import doctest + doctest.testmod() + + import itertools + + for perm in itertools.permutations(testdata): + if strategy_forcedsequence(testdata[:]) != strategy_forcedsequence_timsort(testdata[:]): + print "difference for testdata", testdata + print "normal", strategy_forcedsequence(testdata[:]) + print "timsort", strategy_forcedsequence_timsort(testdata[:])